Problem:
Buktikan bahwa $$\begin{aligned}\tan n\theta &=\frac{\displaystyle\binom{n}{1} \tan \theta - \binom{n}{3} \tan^3\theta+\cdots}{\displaystyle1-\binom{n}{2} \tan^2\theta+\cdots}\end{aligned}$$
Solusi:
Buktikan bahwa $$\begin{aligned}\tan n\theta &=\frac{\displaystyle\binom{n}{1} \tan \theta - \binom{n}{3} \tan^3\theta+\cdots}{\displaystyle1-\binom{n}{2} \tan^2\theta+\cdots}\end{aligned}$$
Solusi:
